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Question

A man of mass 60kg standing on an elevator moves down with acceleration 2m/s2. Find the change percentage of apparent weight of man

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Solution

Given,
weight of man =60kg
downwards acceleration =2m/s2
Now, when lift moves downwards
w2=m(ga)
=60(102)m/s2
=480N
Again, w1=mg
w1=60×10=600N
Now, change percentage of apparent weight
=w1w2w1×100
600480600×100=20%
change is 20%.

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