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Question

A man of mass m pulls a block with mass M with a rope. The block moves towards the right direction as shown in the figure below:

The magnitude of friction is the same between the man and the ground and between the block and the ground. If T is the tension on the rope, f is the frictional force acting on the block, which of the following expression correctly depicts the force experienced by the block ?


  1. Tf=M×aB

  2. Tf=MaB

  3. T+f=M×aB

  4. Tf=M×aB


Solution

The correct option is B

Tf=MaB


Assume the acceleration of the block to be aB. Tension on the block is acting towards the right. 
We know friction opposes motion so f is towards the left. In order for the block to move tension must be greater than f. The force experienced by the block which is
M×aB will be equal to Tf=M×aB

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