Question

# A man starts his job with a certain monthly salary and earns a fixed increment every year. If his salary was $₹1500$ after $4$ year of service and $₹1800$ after $10$ years of service, what was his starting salary and what is the annual increment?

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Solution

## Let $₹x$ be the starting salary of a man and $₹y$ be the fixed annual increment.Then,Salary after $4$ years of service $=₹\left(x+4y\right)$Salary after $10$ years of service $=₹\left(x+10y\right)$As per the question, given that,$\left(x+4y\right)=₹1500$…………eq.$1$$\left(x+10y\right)=₹1800$………..eq.$2$On subtracting equation ($1$) from equation ($2$), we get,$6y=300$$y=\frac{300}{6}=50$Substituting $y=50$ in equation ($1$), we get,$x+4×50=1500$$x+200=1500$$x=1500-200$$x=1300$Therefore, the starting salary of a man was $₹1300$ and the annual increment is $₹50$.

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