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Question

A man starts his job with a certain monthly salary and earns a fixed increment every year. If his salary was 1500 after 4 year of service and 1800 after 10 years of service, what was his starting salary and what is the annual increment?


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Solution

Let x be the starting salary of a man and y be the fixed annual increment.

Then,

Salary after 4 years of service =(x+4y)

Salary after 10 years of service =(x+10y)

As per the question, given that,

(x+4y)=1500…………eq.1

(x+10y)=1800………..eq.2

On subtracting equation (1) from equation (2), we get,

6y=300

y=3006=50

Substituting y=50 in equation (1), we get,

x+4×50=1500

x+200=1500

x=1500-200

x=1300

Therefore, the starting salary of a man was 1300 and the annual increment is 50.


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