CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A man starts his job with a certain salary and earns a fixed increment every year. If his salary was ₹15000 after 4 years of service and ₹18000 after 10 years of service, then find his starting salary and annual increment respectively.

A
₹11000, ₹700
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
₹13000, ₹500
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
₹13000, ₹700
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
₹11000, ₹500
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B ₹13000, ₹500
Let starting salary be ₹x
and annual increment be ₹y
According to the first condition:
x + 4y = 15000 ......(i)
According to the second condition:
x + 10y = 18000 ......(ii)
Subtracting (i) from (ii), we get
6y = 3000
y = 500
Substituting y = 500 in equation (i), we get
x + (4×500) = 15000
x = 15000 - 2000
x = 13000
Hence, starting salary is ₹13000 and annual increment is ₹500.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Algebraic Solution
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon