CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A man throws ball with the same speed vertically upwards one after the other at an interval of 2 seconds. What should be the speed of the throw so that more than two balls are in the sky at any time ? (Given g=9.8m/s2)

A
More than 19.6m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
At least 9.8m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Any speed less than 19.6m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Only with speed 19.6m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C More than 19.6m/s
The correct option is A.
We have t=2s
When the ball is thrown upward the final velocity become zero.
Therefore,

v=u+at

0=ugt

Here, g is acceleration due to gravity

u=gt

=9.8×2=19.6 m/s

Thus, when he throws a ball with a minimum speed of 19.6m/s in a time interval of 2s.
Then two balls can be in the air simultaneously.

956281_69472_ans_96cc4ad66eae42a58ca890cc927efeb6.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Free Fall
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon