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Question

A man uses $$1.71gm$$ sugar then used number of carbon atoms will be:


A
3.6×1022
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B
7.2×1021
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C
0.05
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D
6.6×!022
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Solution

The correct option is A $$3.6\times {10}^{22}$$
Moles of sucrose$$(C_{12}H_{22}O{11})=\cfrac {1.71}{342}=5\times 10^{ -3 }$$
Number of molecules of sucrose=$$5\times 10^{ -3 }\times 6.022\times 10^{ 23 }$$
=$$3.011\times 10^{ 21 }$$

But $$1$$ molecule of sucrose contains $$12$$ atoms of Carbon.

$$\therefore$$  Number of Carbon atoms= $$12\times 3.011\times 10^{ 21 }$$
=$$3.6\times 10^{ 22 }$$

Chemistry

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