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Question
A man walks 1 km towards East, turns to South and walks 5 km. Again he turns to East and walks 2 km, after which he turns to North and walks 9 km. How far is he from his starting point?
A man walks 1 km towards East, turns to South and walks 5 km. Again he turns to East and walks 2 km, after which he turns to North and walks 9 km. How far is he from his starting point?
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Solution
The correct option is C 5 km
The movements of the man are as shown in the below figure (A to B, B to C, C to D, D to E) Clearly, DF = BC = 5 km
EF = (DE - DF) = (9 - 5) km = 4 km
BF = CD = 2 km
AF = AB + BF = AB + CD = (1 + 2) km = 3 km
Using Pythagoras theorem in ΔAEF, AE = 5km
5 km
The movements of the man are as shown in the below figure (A to B, B to C, C to D, D to E) Clearly, DF = BC = 5 km
EF = (DE - DF) = (9 - 5) km = 4 km
BF = CD = 2 km
AF = AB + BF = AB + CD = (1 + 2) km = 3 km
Using Pythagoras theorem in ΔAEF, AE = 5km
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