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Question

A man walks toward right for 80 m take a right walks for 100 m, take a left walk for 40 cm. again take left and walks for 150 m and stops. The distance from him to initial point is ____________(Enter in digits)


  1. 130


Solution

The correct option is A

130


The person travels along the path ABCDE

As per question, AB = 80 cm       CD = 40 cm

                           BC = 100 cm     DE = 150 cm

We can observe EK = (150 - 100) = 50 cm

Now, AE is the distance from him to initial point

Using pythagoras theorem, we get

AE2=AK2+EK2AE2=(80+40)2+(50)2AE2=(120)2+(50)2AE2=14400+2500AE2=16900 AE=130 cm

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