A man weighs $80 k g$ . He stands on a weighing scale in a lift that is moving upwards with a uniform acceleration of $5 m s^{- 2}$ . What would be the reading on the scale? $(g = 10 m s^{- 2})$

$400 N$

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$800 N$

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$1200 N$

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$Z e r o$

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Solution

The correct option is C
$1200 N$

Step 1. Given Data:
Acceleration due to gravity $(g) = 10 m s^{- 2}$
Weight of the man $(m) = 80 K g$
Acceleration of lift $(a) = 5 m s^{- 2}$
Step 2. Balancing forces acting on the man:
Normal reaction, $N$ acting opposite to the weight
$\sum_{}^{} F = m a m a = N - m g \Rightarrow N = m (g + a) \Rightarrow N = 80 (10 + 5) \Rightarrow N = 1200 N$
Hence, option $(C)$ is correct.

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Q. A man weighs 80 kg He stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of

5 m / s^{2} .

What would be the reading on the scale ?

(g = 10 m / s^{2})

A man weighs $80 k g$ . He stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of $5 m / s^{2}$ . What would be the reading on the scale?

Q. A man weighs

80 k g

. He stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of

5 m / s^{2}

. What would be the reading on the scale? (

g = 10 m / s^{2}

)

A man weighs 70 kg. He stands on a weighing scale in a lift which is moving upwards with an acceleration of 5ms².What would be the reading on the scale? (g=10 ms²).

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