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Question

A mason constructs a wall of dimensions $$270$$ cm $$\times$$ $$300$$ cm $$\times$$ $$350$$ cm with the bricks each of size $$22.5$$ cm $$\times$$ $$11.25$$ cm $$\times$$ $$8.75$$ cm and it is assumed that $$\dfrac{1}{8}$$ space is covered by the mortar. Then the number of bricks used to construct the wall is


A
11100
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B
11200
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C
11000
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D
11300
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Solution

The correct option is B $$11200$$
Volume of wall$$=(270)(300)(350)=28350000 cm^3$$

Volume of brick$$=(22.5)(11.25)(8.75)=2214.84375  cm^3$$

$$\displaystyle \frac{1}{8}$$ space is covered by morter $$\displaystyle =\frac{28350000}{8} =3543750  $$ 

Surface constructed$$=28350000-3543750=24806250$$

Number of bricks$$\displaystyle =\frac{24806250}{2214.84375}=11200$$

Mathematics

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