Question

# A mason constructs a wall of dimensions $$270$$ cm $$\times$$ $$300$$ cm $$\times$$ $$350$$ cm with the bricks each of size $$22.5$$ cm $$\times$$ $$11.25$$ cm $$\times$$ $$8.75$$ cm and it is assumed that $$\dfrac{1}{8}$$ space is covered by the mortar. Then the number of bricks used to construct the wall is

A
11100
B
11200
C
11000
D
11300

Solution

## The correct option is B $$11200$$Volume of wall$$=(270)(300)(350)=28350000 cm^3$$Volume of brick$$=(22.5)(11.25)(8.75)=2214.84375 cm^3$$$$\displaystyle \frac{1}{8}$$ space is covered by morter $$\displaystyle =\frac{28350000}{8} =3543750$$ Surface constructed$$=28350000-3543750=24806250$$Number of bricks$$\displaystyle =\frac{24806250}{2214.84375}=11200$$Mathematics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More