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Question

A match box measures $$4$$ $$cm$$ $$\times 2.5$$ $$cm$$ $$\times 1.5$$ $$cm$$. What will be the volume of a packet containing $$12$$ such boxes?


Solution

Given:
$$l=4$$, $$b=2.5$$, $$h=1.5$$

$$V=l\times b\times h$$

    $$=4\times 2.5\times 1.5$$cm$$^{2}$$

    $$=15$$cm$$^{3}$$

Volume of $$12$$ matchboxes 
$$=12\times 15$$cm$$^{3}$$
$$=180$$cm$$^{3}$$

Mathematics
RS Agarwal
Standard IX

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