Question

A match box measures 4 cm $\times$ 2.5 cm $\times$ 1.5 cm. Which of the following does not represent the volume of a packet containing 12 such boxes?

• A. $12\times 15c{m}^3$
• B. $(12\times 4\times 2.5\times 1.5)c{m}^3$
• C. $180c{m}^3$
• D. $(4\times 2.5\times 1.5)c{m}^3$

Answer 1

The correct option is D

$(4\times 2.5\times 1.5)c{m}^3$

Volume of one match box
$=(4\times 2.5\times 1.5)c{m}^3=15c{m}^3$
$\therefore$ Required volume = Volume of 12 match boxes
$=12\times 15c{m}^3=180c{m}^3$