A matchbox measures $4 c m$ by $2.5 c m$ by $1.5 c m$ . What will be the volume of a packet containing $12$ such matchboxes.

Open in App

Solution

STEP 1 : Finding the volume of one matchbox
Length (l) $= 4 c m$
Breadth (b) $= 2.5 c m$
Height (h) $= 1.5 c m$
Volume of a matchbox $= l \times b \times h$
Volume of a matchbox $= 4 \times 2.5 \times 1.5 = 15 c m^{3}$
STEP 2 : Finding the volume of a packet containing $12$ such matchboxes
Volume of packet containing $12$ such matchboxes $= 12 \times v o l u m e o f a m a t c h b o x$
Volume of packet containing $12$ such matchboxes $= 12 \times 15 = 180 c m^{3}$
Hence, the volume of a packet containing $12$ such matchboxes is $180 c m^{3}$ .

Suggest Corrections

Similar questions

$A matchbox measures 4 c m \times 2.5 c m, What is the volume of a packet containig 12 such matchboxes?$

4

\times

2.5

\times

1.5

12

Question 1
A matchbox measures $4 c m \times 2.5 c m \times 1.5 c m$ . What will be the volume of a packet containing 12 such boxes?

Join BYJU'S Learning Program