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Question

A matchbox measures $$ 4 \mathrm{cm} \times 2.5 \mathrm{cm} \times 1.5 \mathrm{cm} .  $$ What will be the volume of a packet containing $$12$$ such boxes?


Solution

VOLUME: 
The space occupied by an object is called the volume of the particular object.
Volume is always measured in cubic unit.

Given:
Dimensions of the matchbox $$= 4 \text{ cm} \times 2.5 \text{ cm} \times 1.5 \text{ cm}$$
So, $$l = 4 \text{ cm}$$, $$b = 2.5 \text{ cm}$$ and $$h = 1.5 \text{ cm}$$
Volume of cuboid $$= (l × b × h)$$
Volume of one matchbox =  Volume of cuboid
Volume of one matchbox $$=4 × 2.5× 1.5$$
$$= 15 \text{ cm}^3$$
Volume of a packet containing $$12$$ such boxes $$= 12\; \times$$ volume of one match box
$$= (12 ×15)  \text{ cm}^3 = 180\text{ cm}^3$$

Hence, the volume of a packet containing $$12$$ such boxes $$= 180$$ $$\text{cm}^3$$

Mathematics

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