Question

# A matchbox measures $$4 \mathrm{cm} \times 2.5 \mathrm{cm} \times 1.5 \mathrm{cm} .$$ What will be the volume of a packet containing $$12$$ such boxes?

Solution

## VOLUME: The space occupied by an object is called the volume of the particular object.Volume is always measured in cubic unit.Given:Dimensions of the matchbox $$= 4 \text{ cm} \times 2.5 \text{ cm} \times 1.5 \text{ cm}$$So, $$l = 4 \text{ cm}$$, $$b = 2.5 \text{ cm}$$ and $$h = 1.5 \text{ cm}$$Volume of cuboid $$= (l × b × h)$$Volume of one matchbox =  Volume of cuboidVolume of one matchbox $$=4 × 2.5× 1.5$$$$= 15 \text{ cm}^3$$Volume of a packet containing $$12$$ such boxes $$= 12\; \times$$ volume of one match box$$= (12 ×15) \text{ cm}^3 = 180\text{ cm}^3$$Hence, the volume of a packet containing $$12$$ such boxes $$= 180$$ $$\text{cm}^3$$Mathematics

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