CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A material has Poisson's ratio 0.50. If a uniform rod of it suffers a longitudinal strain of 2×103, then the percentage change in volume is

A
0.6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
zero
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is C zero
Given: dLL=2×103
Poisson's ratio, σ=drrdLL
where, r and L are the radius and length of the rod respectively
0.5=drr2×103

drr=103

Volume of the rod, V=πr2L
Differentiating, we get, dV=π(r2dL+2Lrdr)

dVV×100=π(r2dL+2rLdr)πr2L×100=(dLL+2drr)×100

dVV×100=[2×103+2(103)]×100=0

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Hooke's Law
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon