Question

A member is made of structural steel;. When it is subjected to simple tension, the limit of proportionality is 280 $N/m{m}^2$. If the principal stresses $p_{1}and{p}_2$ developed in the member are 100 $N/m{m}^2$ (tensile) and 40 $N/m{m}^2$ (compressive) respectively and Poisson's ratio is 0.30, then the factor of safety according to maximum shear stress theory would be

• A. 2.75
• B. 2.5
• C. 2.25
• D. 2.0

Answer 1

The correct option is D 2.0

Maximum shear stress,
${\tau }_{max}=\frac{100-(-40)}{2}=70N/m{m}^2$
$Factorofsafety=\frac{\left({\sigma }_y/2\right)}{{\tau }_{max}}=\frac{\left(280/2\right)}{70}$
= 2