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Question

# A metal ball of mass 2 kg moving with a velocity of 36 km/h has a head on collision with a stationary ball of mass 3 kg. If after the collision, the two balls move together, the loss in kinetic energy due to collision is.

A
140 J
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B
100 J
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C
60 J
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D
40 J
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Solution

## The correct option is C 60 JApply conservation of momentum, m1v1=(m1+m2)vv=m1v1(m1+m2)Here v1=36km/hr=10m/s,m1=2kg,m2=3kgv=10×25=4m/sK.E. (initial) =12×2×(10)2=100JK.E. (Final) =12×(3+2)×(4)2=40JLoss in K.E. =100−40=60JAlternatively use the formula−ΔEk=12m1m2(m1+m2)(u1−u2)2

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