Question

A metal $M$ forms a sulphate which is isomorphous with $MgS{O}_4.7H_{2}O$. If 0.6538 g of metal $M$ displaced 2. 16 g of silver from silver nitrate solution, then the atomic weight of the metal $M$ is:

• A. $32.61$
• B. $56.82$
• C. $65.38$
• D. $74.58$

Answer 1

The correct option is C $65.38$

We can use,

$\frac{w_1}{E_1}=\frac{w_2}{E_2}$

$\frac{0.638}{E_1}=\frac{2.16}{108}$

$E_1=32.69$

Hence,atomic weight of metal would be $32.69\times 2=65.38$

Here, 2 is the valency factor.

So, the correct option is $C$