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Standard XII

Physics

New Capacitance in Dielectric

A metal plate...

Question

A metal plate of thickness $d / 2$ is introduced in between the plates of a parallel plate air capacitor with plate separation of $d$ . Capacity of the metal plate :

Decreases

2

times

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Increases

2

times

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Remains same

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Becomes zero

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Solution

The correct option is C Increases $2$ times
$C = \frac{ϵ_{o} A}{d}$
when a dielectric is filled ,thickness t
$C_{1} = \frac{ϵ_{o} A}{d - t + \frac{t}{K}}$
for metal k= infinity , $t = \frac{d}{2}$
$C_{1} = \frac{2 ϵ_{o} A}{d} = 2 C$

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A metal plate of thickness d/2 is introduced in between the plates of a parallel plate air capacitor with plate separation of d. Capacity of the metal plate :

The correct option is C Increases 2 timesC=ϵoAdwhen a dielectric is filled ,thickness tC1=ϵoAd−t+tKfor metal k= infinity ,t=d2C1=2ϵoAd=2C

A metal plate of thickness $d / 2$ is introduced in between the plates of a parallel plate air capacitor with plate separation of $d$ . Capacity of the metal plate :

The correct option is C Increases $2$ times
$C = \frac{ϵ_{o} A}{d}$
when a dielectric is filled ,thickness t
$C_{1} = \frac{ϵ_{o} A}{d - t + \frac{t}{K}}$
for metal k= infinity , $t = \frac{d}{2}$
$C_{1} = \frac{2 ϵ_{o} A}{d} = 2 C$