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Question

A metal stick of mass 1 kg and length 1 metre is held vertically with one end on the floor and is then allowed to fall. All values are in SI units. Take approximations.
Column-IColumn-II(a) Initial mechanical energy(p)5.425(b)(Angular velocity) 2 just before hitting the ground(q) 29.429(c) Linear velocity of the free end just before hitting the ground(r) 4.9(d) Moment of inertia(s) 0.333

A
ap;bq;cr;dp
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B
ar;bq;cp;ds
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C
aq;br;cp;ds
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D
ar;bq;cs;dp
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Solution

The correct option is B ar;bq;cp;ds
(a)(r);(b)(q);(c)(p);(d)(s)
Moment of inertia = 13×1×1=0.33
Mechanical energy = 1×9.8×12=4.9
By M.E. conservation
also, 12×13×1×ω2=4.9
ω2=6×4.9=29.4For free endv=ωl=ω=5.425

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