CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

A metal wire of linear mass density of 9.8g/m is stretched with a tension of 10kgwt between two rigid supports 1m apart. The wire passes at its middle point between the poles of a permanent magnet and it vibrates in resonance when carrying an alternating current of frequency n. The frequency n of the alternating source is

A
50Hz
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
100Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
200Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
25Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 50Hz
When in resonance, the frequency of alternating current must be equal to the fundamental frequency of vibration of the metal wire.
Thus f=12lTμ
=1210×9.89.8×103=50Hz

flag
Suggest Corrections
thumbs-up
0
mid-banner-image
mid-banner-image
similar_icon
Related Videos
thumbnail
lock
Normal Modes on a String
PHYSICS
Watch in App