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Question

# A metal X reacts with aqueous NaOH solution to form Y and a highly inflammable gas. Solution Y is heated and CO2 IS poured through it. Z precipitates out and Na2CO3 is formed. Z on heating gives Al2O3. Identify X, Y and Z.

A
AlX, NaAlO2Y, Al(OH)3Z
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B
Al2O3X, NaAlO2Y, Al2CO3Z
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C
Al2O3X, [Na2AlO2]+OhY, Al(OH)3Z
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D
Al-X, Al(OH)3Y, Al2O3Z
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Solution

## The correct option is C Al−X, NaAlO2−Y, Al(OH)3−ZSolution:-X+NaOH(aq)⟶Y+highly inflammable gasY+CO2+H2O⟶Z+Na2CO3Z−−−−−−−→OnheatingAl2O3Al2O3 is formed when Al(OH)3 is heated. 2Al(OH)3−−−−−−−→OnheatingAl2O3+3H2OThus Z is Al(OH)3.When NaAlO2 is heated and CO2 is poured through it, Al(OH)3 precipitates out and Na2CO3 is formed.2NaAlO2+CO2+3H2O⟶2Al(OH)3+Na2CO3Thus Y is NaAlO2When Al reacts with aqueous NaOH solution, it forms NaAlO2andH2(Highly inflammable gas)Al+NaOH(aq)⟶NaAlO2+H2(highly inflammable gas)Thus X is Al.Hence, (A) is correct answer.

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