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Question
A metallic block carrying current I is subjected to a uniform magnetic field →B as shown in the figure. The moving charges experience a force →F given by ........... which results in the lowering of the potential of the face ........ Assume the speed of the carriers to be v
A metallic block carrying current I is subjected to a uniform magnetic field →B as shown in the figure. The moving charges experience a force →F given by ........... which results in the lowering of the potential of the face ........ Assume the speed of the carriers to be v
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Solution
The correct option is D −eVB^k,EFGH
As the block is of metal, the charge carriers are electrons, so for current along positive x-axis, the electrons are moving along negative x-axis, i.e. →v=−v^i
and, as the magnetic field is along the y-axis, i.e. →B=B^j
so,→F=q(→v×→B)forthiscaseyield→F=(e)[−v^i×B^j]
i.e., →F=−evB^k[As ^i×^j=^k]
As force on electrons is towards the face EFGH, the electrons will accumulate on it an hence it will acquire lower potential.
As the block is of metal, the charge carriers are electrons, so for current along positive x-axis, the electrons are moving along negative x-axis, i.e. →v=−v^i
and, as the magnetic field is along the y-axis, i.e. →B=B^j
so,→F=q(→v×→B)forthiscaseyield→F=(e)[−v^i×B^j]
i.e., →F=−evB^k[As ^i×^j=^k]
As force on electrons is towards the face EFGH, the electrons will accumulate on it an hence it will acquire lower potential.
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