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Question

A metallic disc is being heated. Its area A (in m2) at any time T (in second) is given by A=5t2+4t+8. Calculate the rate of increase in area at T=3s


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Solution

Step 1. Given data:

Area A=5t2+4t+8

Time =3s

Step 2. Calculating rate of increase in area:

The rate of increase in area = dAdt=10t+4

At time T=3s

dAdt=103+4=34m2s-1

Therefore, the rate at which area increases at T=3s is 34m2s-1.


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