Question

# A metallic ring of radius 'r', cross sectional area 'A' is fitted into a wooden circular disk of radius 'R' (R > r). If the Young's modulus of the material of the ring is 'Y', the force with which the metal ring expands is :

A
AYRr
B
AY(Rr)r
C
Y(Rr)Ar
D
YRAr

Solution

## The correct option is B $$\dfrac{AY(R-r)}{r}$$$$Y = \dfrac{F/A}{\triangle l/l}$$         (standard result)$$F = \dfrac{Y \triangle l A}{l}$$$$= \dfrac{Y (R-r) A}{r} (\because \triangle l = R-r)$$Physics

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