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Question

A meter bridge is set-up as shown, to determine an unknown resistance $$X$$ using a standard $$10\ ohm$$ resistor. The galvanometer shows null point when tapping-key is at $$52\ cm$$ mark. The end-corrections are $$1\ cm$$ and $$2\ cm$$ respectively for the ends $$A$$ and $$B$$. The determined value of $$'X' $$ is:

28715.PNG


A
10.2 ohm
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B
10.6 ohm
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C
10.8 ohm
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D
11.1 ohm
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Solution

The correct option is B $$10.6\ ohm$$
Balancing the circuit ,
$$X\times(48+2) = 10\times(52+1)$$
$$\displaystyle X= \frac{530}{50}=10.6  ohms$$

Physics
NCERT
Standard XII

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