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Standard XII

Physics

Meter Bridge

A meter bridg...

Question

A meter bridge is set-up as shown, to determine an unknown resistance $X$ using a standard $10 o h m$ resistor. The galvanometer shows null point when tapping-key is at $52 c m$ mark. The end-corrections are $1 c m$ and $2 c m$ respectively for the ends $A$ and $B$ . The determined value of $^{'} X^{'}$ is:

10.2 o h m

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10.6 o h m

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10.8 o h m

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11.1 o h m

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Solution

The correct option is B $10.6 o h m$
Balancing the circuit ,
$X \times (48 + 2) = 10 \times (52 + 1)$
$X = \frac{530}{50} = 10.6 o h m s$

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(a) In a metre bridge [Fig. 3.27], the balance point is found to be at 39.5 cm from the end A, when the resistor Y is of 12.5 Ω. Determine the resistance of X. Why are the connections between resistors in a Wheatstone or meter bridge made of thick copper strips?

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Q. Shown in the figure is a meter-bridge set up with null deflection in the galvanometer. The value of the unknown resistance R is?

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A meter bridge is set-up as shown, to determine an unknown resistance X using a standard 10 ohm resistor. The galvanometer shows null point when tapping-key is at 52 cm mark. The end-corrections are 1 cm and 2 cm respectively for the ends A and B. The determined value of ′X′ is:

The correct option is B 10.6 ohmBalancing the circuit ,X×(48+2)=10×(52+1)X=53050=10.6ohms

The correct option is B $10.6 o h m$
Balancing the circuit ,
$X \times (48 + 2) = 10 \times (52 + 1)$
$X = \frac{530}{50} = 10.6 o h m s$