Question

# A meter bridge is set-up as shown, to determine an unknown resistance $$X$$ using a standard $$10\ ohm$$ resistor. The galvanometer shows null point when tapping-key is at $$52\ cm$$ mark. The end-corrections are $$1\ cm$$ and $$2\ cm$$ respectively for the ends $$A$$ and $$B$$. The determined value of $$'X'$$ is:

A
10.2 ohm
B
10.6 ohm
C
10.8 ohm
D
11.1 ohm

Solution

## The correct option is B $$10.6\ ohm$$Balancing the circuit ,$$X\times(48+2) = 10\times(52+1)$$$$\displaystyle X= \frac{530}{50}=10.6 ohms$$PhysicsNCERTStandard XII

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