A milk man has $80$ litres of mixture which contains $40 %$ water. If he sells $20$ litres of the mixture to his customers and adds $x$ litres of pure milk to the remaining, then the ratio of milk to water in the mixture becomes $13 : 2$ . Find the value of $x$ (in litres).

300

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140

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120

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180

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Solution

The correct option is C $120$
60 litres mixture (after selling 20 litres).
$40 %$ water $\Rightarrow$ 24 litres water & 36 litres milk.
Now, According to the question
$36 + x : 24 = 13 : 2$
$\Rightarrow 36 + x : 24 = 156 : 24$
$\Rightarrow 36 + x = 156$
$\Rightarrow x = 120$

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A milk man has 80 litres of mixture which contains 40% water. If he sells 20 litres of the mixture to his customers and adds x litres of pure milk to the remaining, then the ratio of milk to water in the mixture becomes 13:2. Find the value of x (in litres).

The correct option is C 12060 litres mixture (after selling 20 litres).40% water ⇒ 24 litres water & 36 litres milk.Now, According to the question36+x:24=13:2⇒36+x:24=156:24⇒36+x=156⇒x=120

A milk man has $80$ litres of mixture which contains $40 %$ water. If he sells $20$ litres of the mixture to his customers and adds $x$ litres of pure milk to the remaining, then the ratio of milk to water in the mixture becomes $13 : 2$ . Find the value of $x$ (in litres).

The correct option is C $120$
60 litres mixture (after selling 20 litres).
$40 %$ water $\Rightarrow$ 24 litres water & 36 litres milk.
Now, According to the question
$36 + x : 24 = 13 : 2$
$\Rightarrow 36 + x : 24 = 156 : 24$
$\Rightarrow 36 + x = 156$
$\Rightarrow x = 120$