A milkman purchases certain litres of milk at a rate of ₹ 45 per litre and certain litres of milk at ₹ 51 per litre .selling all the milk for ₹1200, he made a profit of ₹150.if he had purchased 22 litres of milk, find the quantities of milk purchased at each rate.

Open in App

Solution

Let X denote milk at 45 rs
Y denote milk at 51 rs
Given,
total cost+ profit=1200
Profit= 150
therefore, total cost=1200-150=1050
hence 45X+51Y = 1050
and total milk sold is 22 ltrs
That is, X+Y=22
solving these two equations we get
X= milk at 45 rs = 12 ltr
Y= milk at 51 rs = 10 ltr

Suggest Corrections

Similar questions

A milkman purchases milk at the rate of ₹12 per litre and then mixes $25 %$ water to it. Find his profit $%$ , if he sells the mixture at ₹ 15 per litre.

Q. A milkman purchases the milk at Rs.

x

per litre and sells it at Rs.

2 x

per litre still he mixes

2

litres water with every

6

litres of pure milk. What is the profit percentage?

A milkman purchases milk at the rate of Rs 12 per litre and then mixes 25% water to it. Find his profit %, if he sells the mixture at Rs 15 per litre.

Q. A milkman purchases milk at the rate of Rs. 12 per litre and then mixes 25 per cent water to it. Find his profit per cent, if he sells the mixture at Rs. 15 per litre.

Q. A milkman purchases milk at Rs

20 /

litre and mixes

4

litres of water in it. By selling the resultant mixture at the rate of Rs

20 /

litre, he earns a profit of

40 %

. The percentage of milk in the mixture he had with him to sell was

Join BYJU'S Learning Program

A milkman purchases certain litres of milk at a rate of ₹ 45 per litre and certain litres of milk at ₹ 51 per litre .selling all the milk for ₹1200, he made a profit of ₹150.if he had purchased 22 litres of milk, find the quantities of milk purchased at each rate.

Let X denote milk at 45 rs Y denote milk at 51 rs Given, total cost+ profit=1200 Profit= 150 therefore, total cost=1200-150=1050 hence 45X+51Y = 1050 and total milk sold is 22 ltrs That is, X+Y=22 solving these two equations we get X= milk at 45 rs = 12 ltr Y= milk at 51 rs = 10 ltr

Let X denote milk at 45 rs
Y denote milk at 51 rs
Given,
total cost+ profit=1200
Profit= 150
therefore, total cost=1200-150=1050
hence 45X+51Y = 1050
and total milk sold is 22 ltrs
That is, X+Y=22
solving these two equations we get
X= milk at 45 rs = 12 ltr
Y= milk at 51 rs = 10 ltr