Question

A mixture contains $n_1$ moles of monoatomic gas and $n_2$ moles of diatomic gas. If $\gamma =1.50$ for mixture, the ration of $\frac{n_1}{n_2}$ is _____.

Answer 1

${\gamma }_{monoatomic}=5/3$

${\gamma }_{diatomic}=7/5$

${\gamma }_{mixture}=\frac{(n_1\times 5/3+n_2\times 7/5)}{n_1+n_2}$

$1.50n_1+1.50n_2=\frac{5n_1}{3}+\frac{7n_2}{5}$

$0.167n_1=0.1n_2$

$\frac{n_1}{n_2}\approx 1$

Hence, correct answer is 1.