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Limiting Reagent or Reactant

A mixture of ...

Question

A mixture of $C_{3} H_{8}$ (g) & $O_{2}$ having total volume 100 ml in an Eudiometry tube is sparked & it is observed that a contraction of 45 ml is observed what can be the composition of reacting mixture.

A

15 m l C_{3} H_{8}

&

85 m l O_{2}

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B

25 m l C_{3} H_{8}

&

75 m l O_{2}

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C

45 m l C_{3} H_{8}

&

55 m l O_{2}

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D

55 m l C_{3} H_{8}

&

45 m l O_{2}

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Solution

The correct options are
A $15 m l C_{3} H_{8}$ & $85 m l O_{2}$
C $25 m l C_{3} H_{8}$ & $75 m l O_{2}$
$C_{3} H_{8} (g) + 5 O_{2} (g) \to 3 C O_{2} (g) + 4 H_{2} O (l)$
1 mole of porpane reacts with 5 moles of oxygen to form 3 moles of carbon dioxide.
The number of moles is directly proportional to the volume of the gas.
Thus when 15 ml of propane reacts with 75 ml of oxygen, 45 ml of carbon dioxide will be obtained.
The contraction in the volume will be $15 + 75 - 45 = 45 m l$ .
This is possible when the composition of the reacting mixture is either $15 m l C_{3} H_{8} a n d 85 m l O_{2}$ or $25 m l C_{3} H_{8} a n d 75 m l O_{2}$ .
Hence, options A and B are the correct answers.

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