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Question

A mixture of CO and CO2 is found to have a density of 1.5 gm/L at 30oC and 740 mm pressure. The percentage composition of CO2 in the mixture is:

A
64.5%
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B
61.5%
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C
74.5%
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D
71.5%
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Solution

The correct option is A 64.5%
PV=nRT
PV=massmoleularweightRT
massV=P×moleularweightRT
d=P×MavgRT, where Mavg is the molecular weight of the mixture.
1.5=740760×Mavg0.0821×303
Let x be the percentage composition of CO2 in the mixture.
Mavg=38.32=x×44+(100x)×28100
x=64.5%.

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