A mixture of ethyl iodide and n-propyl iodide is subjected to wurtz reaction. The hydrocarbon which will be majorly formed is:

butane

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propane

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pentane

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hexane

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Solution

The correct option is C pentane
Wurtz reaction: $R X + 2 N a + X R \to R - R + 2 N a X$
So pentane will form.

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By Wurtz reaction, a mixture of ethyl iodide and methyl iodide gives:

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