A mixture of hydrogen and oxygen has volume 2000cm3, temperature 300K, pressure 100kPa and mass 0.76g. The ratio of number of moles of hydrogen to number of moles of oxygen in the mixture will be:
[Take gas constant R=8.3JK−1mol−1]
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Solution
From ideal gas law: P1V=n1RT P2V=n2RT
Adding both the equations : (100kPa)V=(n1+n2)RT
⇒n1+n2=(100kPa)(2000cm3)8.3×300...(1)
Also from mass balance, n1×2+n2×32=0.76...(2)
Solving (1) and (2), n1=0.06 n2=0.02 ⇒n1n2=3