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Question

A mixture of hydrogen and oxygen has volume 2000 cm3, temperature 300 K, pressure 100 kPa and mass 0.76 g. The ratio of number of moles of hydrogen to number of moles of oxygen in the mixture will be:

[Take gas constant R=8.3JK1mol1]

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Solution

From ideal gas law:
P1V=n1RT
P2V=n2RT
Adding both the equations :
(100 kPa)V=(n1+n2)RT

n1+n2=(100 kPa)(2000 cm3)8.3×300...(1)

Also from mass balance, n1×2+n2×32=0.76...(2)
Solving (1) and (2),
n1=0.06
n2=0.02
n1n2=3

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