1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A mixture of one mole of CO2 and one mole of H2 attains equilibrium at 250∘C and 0.1 atm.CO2+H2→CO+H2O Calculate Kp, if the analysis of final reaction mixture shows 0.16 volume percent of CO :

A
2.06×105
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
10.3×105
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1.03×105
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
2.06×105
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 1.03×10−5The equilibrium reaction is CO2+H2→CO+H2O.The following table lists various quantities.CO2, H2, CO, H2OInitial moles: 1 1 0 0Moles at equilibrium: 1−x 1−x x xTotal number of moles =1−x+1−x+x+x=2.For CO, mole % is equal to volume %.Thus x2×100=0.16 or x=0.0032.As, Δn=0, Kc=Kp=x2(1−x)2=(0.0032)2(1−0.0032)2=1.03×10−5.

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Equilibrium Constants
CHEMISTRY
Watch in App
Explore more
Join BYJU'S Learning Program