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Question

# A mixture of one mole of CO2 and one mole of H2 attains equilibrium at a temperature of 250oC and a total pressure of 0.1 atm for the change CO2(g)+H2(g)⇌CO(g)+H2O(g). Calculate KP if the analysis of final reaction mixture shows 0.16 volume percent of CO.

A
KP=1.03×105
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B
KP=1.25×104
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C
KP=5×105
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D
KP=1×103
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Solution

## The correct option is B KP=1.03×10−5CO2(g)+H2(g)⇌CO(g)+H2(g)1 1 0 0 Moles at t=0(1−x) (1−x) x x Moles at equilibriumGiven that volume % of CO=0.16∵ Moles of CO= xThe moles at equilibrium = 1−x+1−x+x+x=2∴x2=0.16100⇒∴x=0.0032KC=KP=x2(1−x)2(∵△n=0,∴Volumetermsarenotneeded)KP=(0.0032)2(1−0.0032)2=1.03×10−5

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