Question

A mixture of sugar and salt contains 30% sugar. Find the weight of salt in 20 kg of the mixture.

• A. $15$ kg
• B. $6$ kg
• C. $7$ kg
• D. $14$ kg

Answer 1

The correct option is D $14$ kg

Given,
Percentage of sugar = 30%
Weight of mixture = 20 kg

Suppose, the weight of sugar is A kg.

Let us write in two forms, the ratio of the total weight of sugar to the total weight of mixture, obtain an equation and solve it.

Then, we have:

$\frac{A}{20}=30\%$

$\Rightarrow \frac{A}{20}=\frac{30}{100}$

$\Rightarrow \frac{A}{20}\times 20=\frac{30}{100}\times 20$

$\Rightarrow A=6$

Hence, the weight of sugar is 6 kg.

Now, the weight of salt = weight of mixture - weight of sugar
$=20-6=14$ kg

$\therefore$ The weight of salt is $14$ kg.