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Question

A mixture of volatile components A and B has total vapour pressure (in torr) as $$P= 254-119{\chi}_{A}$$, where $${\chi}_{A}$$ is the mole fraction of A in the mixture. Hence, $${P}_{A}^{o}$$ and $${P}_{B}^{o}$$ respectively are (in torr):


A
254,119
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B
119, 254
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C
135, 254
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D
154, 119
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Solution

The correct option is B 135, 254
$${P}_{Total}={P}_{A}^{o}{\chi}_{A}+{P}_{B}^{o}{\chi}_{B}$$
            $$={P}_{A}^{o}{\chi}_{A}+{P}_{B}^{o}(1-{\chi}_{A})$$
            $$={P}_{B}^{o}-({P}_{B}^{o}-{P}_{A}^{o}){\chi}_{A}$$
Given equation $$=254 -119{\chi}_{A}$$
Compare with the given equation,
$$\therefore {P}_{B}^{o}=254,{P}_{B}^{o}-{P}_{A}^{o}=119$$
$$\therefore {P}_{A}^{o}=254 -119=135$$

Option C is correct.

Chemistry

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