A monkey is at rest on a weightless rope which goes over a pulley and is tied to a bunch of bananas at the other end. The weight of the bunch of bananas is exactly the same as that of the monkey. The pulley is frictionless and weightless. The monkey starts to climb up the rope to reach the bananas. As he climbs, the distance between him and the bananas will :

decrease

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increase

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first decrease and then increase

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remain unchanged

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Solution

The correct option is D remain unchanged
$W_{m} = W_{m} (g + a) W_{m} = W_{b}$
Since the weight is same.
So acceleration will be zero.
$M_{m} (g + a) = M_{b} g M_{m} = M_{b} M_{m} g + M_{m} a = M_{b} g M_{m} a = 0 a = 0$
Hence acceleration is zero.the distance between him and banana will remain unchanged so the correct answer is D.

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The correct option is D remain unchangedWm=Wm(g+a)Wm=WbSince the weight is same.So acceleration will be zero.Mm(g+a)=MbgMm=MbMmg+Mma=MbgMma=0a=0Hence acceleration is zero.the distance between him and banana will remain unchanged so the correct answer is D.