Question

A monoatomic ideal gas is taken through a cycle ABCA as shown. The efficiency of the cycle is

A

7%

B

10%

C

8.7%

D

15%

Solution

The correct option is D 8.7% Work done = Area =12×P×2V=PV QAB=nCvΔT=CvRV(2P−P)=3PV2 QBC=nCPΔT=CpR2P(3V−V)=10PV η=WQ=2PV23PV×100=8.7%

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