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Question

A monochromatic source of light of wavelength λ operating at 400 W emits 2×1016 photons per second. Now source operates at 600 W & wavelength changes to 3λ, number of photons emitted per second are (Both wavelength are less than threshold wavelength λ0)

A
4×1016
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B
3×1016
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C
9×1016
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D
12×1016
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Solution

The correct option is C 9×1016
P=NhcλN=p.λhcN1N2=P1λ1P2λ2=/400×/λ/600×3/λ=418=29N2=92N1=92×2×1016=9×1016 photons per second

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