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Question

A moving coil galvanometer A has 200 turns and resistance 100 . Another meter B has 100 turns and resistance 40 . All the other quantities are same in both the cases. The current sensistivity of


A
B is double as that of A
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B
A is 2.5 times of B
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C
A is 5 times of B
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D
B is 5 times of A.
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Solution

The correct option is A B is double as that of A
for moving coil galvanometer
$$I=(\dfrac{C}{NBA})\phi $$
$$(\dfrac{\phi }{I})=(\dfrac{NBA}{C})$$
current  sensitivity $$(\dfrac{\phi }{I})=(\dfrac{NBA}{C}) $$
$$\dfrac{current    sensitivity   of A}{current   sensitivity   of B}=\dfrac{N_{1}}{N_{2}}$$
=$$\dfrac{200}{100}$$
=2:1

Physics

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