Question

# A moving coil galvanometer A has 200 turns and resistance 100 . Another meter B has 100 turns and resistance 40 . All the other quantities are same in both the cases. The current sensistivity of

A
B is double as that of A
B
A is 2.5 times of B
C
A is 5 times of B
D
B is 5 times of A.

Solution

## The correct option is A B is double as that of Afor moving coil galvanometer$$I=(\dfrac{C}{NBA})\phi$$$$(\dfrac{\phi }{I})=(\dfrac{NBA}{C})$$current  sensitivity $$(\dfrac{\phi }{I})=(\dfrac{NBA}{C})$$$$\dfrac{current sensitivity of A}{current sensitivity of B}=\dfrac{N_{1}}{N_{2}}$$=$$\dfrac{200}{100}$$=2:1Physics

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