(a) Name the oxide of sulphur which reacts with water to give sulphuric acid.
(b) In the Contact Process, the direct reaction between the oxide of sulphur an water is avoided. In this process; what does the oxide of sulphur react with instead of water and what is the name of the product?
(c) Give the name and formula of the acidic salt which can give sodium ions and sulphate ions in solution.
[5 MARKS]

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Solution

Option a: 1 Mark
Option b: 2 Marks
Option c: 2 Marks

(a) Sulphur trioxide $(S O_{3})$ .
(b) The oxide of sulphur (SO3) reacts with cone. sulphuric acid. The name of the product is oleum.
$S O_{3} + H_{2} S O_{4} \to H_{2} S_{2} O_{7} O l e u m$
(c) Sodium bisulphate $(N a H S O_{4})$
$(N a H S O_{4}) H_{2} O \to N a^{+} + H_{3} O^{+} + S O_{4}^{2 -}$

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Similar questions

Name the oxide of sulphur which reacts with water to give sulphuric acid.
In the contact process, the direct reaction between oxide of sulphur and water is avoided. In this process, what does the oxide of sulphur react with instead of water, and what is the name of the product?

Name the oxide of sulphur which reacts with water to give sulphuric acid.

Q. Sulphuric acid is manufactured by the Contact process.
(a) Give two balanced equations to obtain

S O_{2}

in this process.
(b) Give the conditions for the oxidation of

S O_{2}

.
(c) Why is

H_{2} S O_{4}

not obtained by directly reacting

S O_{3}

with water?
(d) Name the chemical used to dissolve

S O_{3}

and name also the product formed.
(e) Give all the main reactions to this process.
[5 MARKS]

Q. Give the name and formula of the acid salt which gives sodium ions and sulphate ions in solution.

Q. Name the base formed when:
1. Sodium reacts with oxygen
2. Sodium oxide reacts with water
3. Copper oxide reacts with sulphuric acid
4. Sodium hydroxide reacts with (\H_2SO_4\)

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Option a: 1 Mark Option b: 2 Marks Option c: 2 Marks (a) Sulphur trioxide (SO3). (b) The oxide of sulphur (SO3) reacts with cone. sulphuric acid. The name of the product is oleum. SO3+H2SO4→H2S2O7Oleum (c) Sodium bisulphate (NaHSO4) (NaHSO4)H2O→Na++H3O++SO2−4