Question

A neutral atom of an element has a nucleus with nuclear charge $11$ times and mass $23$ times that of hydrogen. The element can form a stable charged ion by:

• A. losing 1 electron
• B. losing 2 electrons
• C. gaining 1 electron
• D. gaining 2 electrons

Answer 1

The correct option is A losing 1 electron

Atomic number of hydrogen $=1$.

$\therefore$ The atomic number of neutral atom $=11$ & electronic configuration $=2,8,1$.

Therefore, on losing one electron, the atom forms the stable noble gas configuration as $2,8$.

So, the correct option is A.