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Question

# A non-reducing sugar "A" on hydrolysis gives two reducing monosaccharides. Sugar A is

A

Glucose

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B

Fructose

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C

Sucrose

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D

Galactose

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Solution

## The correct option is C SucroseExplanation of the correct option:(C) On hydrolysis of sucrose, we get D-glucose and D-fructose.${\mathrm{C}}_{12}{\mathrm{H}}_{22}{\mathrm{O}}_{11}$(sucrose) $+{\mathrm{H}}_{2}\mathrm{O}\underset{}{\overset{}{\to }}$ ${\mathrm{C}}_{6}{\mathrm{H}}_{12}{\mathrm{O}}_{6}$(Glucose) $+{\mathrm{C}}_{6}{\mathrm{H}}_{12}{\mathrm{O}}_{6}$(Fructose)Here, Sucrose is a non-reducing sugar because it can't reduce the Tollen's reagent as it does not have a free carbonyl group. However both glucose and fructose reduce Tollen's reagent gives silver mirror as they have a free carbonyl group. and thus a reducing sugar.Explanation for incorrect options:(A) Glucose is monosaccharides, so they can't be hydrolyzed. Hence option A is incorrect.(B) Fructose is monosaccharides, so they can't be hydrolyzed. Hence option B is incorrect.(D) Galactose is monosaccharides, so they can't be hydrolyzed. Hence option D is incorrect.So, option (C) is correct.

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