A nucleus of mass number A- originally at rest- emits an -particle with speed v- The daughter nucleus recoils with a speed

The correct option is C 4v/(A 4)Equation of α decay: nbsp;^AX ⟶ nbsp;^A 4Y + ^4α By conservation of momentum, 0 = m_Yv_Y + m_αv_α 0 = (A 4)v_Y nbsp; ...

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Standard XII

Physics

Characteristics of Bohr's Atomic Model

A nucleus of ...

Question

A nucleus of mass number $A$ , originally at rest, emits an α-particle with speed $v$ . The daughter nucleus recoils with a speed

2 v / (A + 4)

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4 v / (A + 4)

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4 v / (A - 4)

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2 v / (A - 4)

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Solution

The correct option is C $4 v / (A - 4)$
Equation of α-decay:
$^{A} X ⟶^{A - 4} Y +^{4} α$

By conservation of momentum,
$0 = m_{Y} v_{Y} + m_{α} v_{α}$
$0 = (A - 4) v_{Y} - 4 v$
$v_{Y} = 4 v / (A - 4)$

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A nucleus of mass number A, originally at rest, emits an α-particle with speed v. The daughter nucleus recoils with a speed

The correct option is C 4v/(A−4)Equation of α-decay: AX ⟶ A−4Y+ 4α By conservation of momentum, 0=mYvY+mαvα 0=(A−4)vY−4v vY=4v/(A−4)

A nucleus of mass number $A$ , originally at rest, emits an α-particle with speed $v$ . The daughter nucleus recoils with a speed

The correct option is C $4 v / (A - 4)$
Equation of α-decay:
$^{A} X ⟶^{A - 4} Y +^{4} α$

By conservation of momentum,
$0 = m_{Y} v_{Y} + m_{α} v_{α}$
$0 = (A - 4) v_{Y} - 4 v$
$v_{Y} = 4 v / (A - 4)$