A number consists of two digits whose sum is five. When the digits are reversed the number becomes greater by nine. Find the number.
We have to find a two-digit number whose sum of digits is and when the digits are reversed the number becomes greater by .
Let the digit at ten's place be .
Then the digit at one's place (since the sum of digits is )
Thus the number
The number formed by reversing the digits
According to the question,
Therefore the digit at ten's place is .
The digit at one's place
Then the number
Therefore the required number is .