Question

A number is first increased by $20\%$ and the resulting number is then decreased by $10\%$. Find the overall change in the number as percent.

• A. $10\%$ increase
• B. $8\%$ increase
• C. $12\%$ increase
• D. $9\%$ increase

Answer 1

Answer: (B)

$8\%$ increase

Let the number be $x$
First number $=\frac{120}{100}x$
Second number $=\frac{90}{100}\times \frac{120}{100}x=1.08x$
So, overall change in the number $\frac{1.08x-x}{x}\times 100=0.08\times 100=8$ % increase.