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Question

A open ended mercury manometer is used to measure the pressure exerted by a trapped gas as shown in the figure. Initially manometer shows no difference in mercury level in both columns as shown in diagram. 

After sparking $$'A'$$ dissociates according to following reaction 

$$A(g) \rightarrow B(g) + 3C (g)$$

If pressure of Gas $$"A"$$ decreases to $$0.9 \:atm$$. Then:

(Assume temperature to be constant and is $$300 K$$)


140984_96b1602c636141cd87b7bda72ad37316.png


A
total pressure increased to 1.3atm
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B
total pressure increased by 0.3atm
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C
total pressure increased by 22.3cm of Hg
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D
difference in mercury level is 228mm.
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Solution

The correct options are
A total pressure increased to $$1.3\: atm$$
B total pressure increased by $$0.3\: atm$$
D difference in mercury level is $$228\: mm$$.
The change in the number of moles $$\Delta n = 4-1=3$$
Initial pressure is equal to 76 $$cm$$ of mercury or 1 $$atm$$.
$$1-0.9=0.1$$ $$atm$$ of $$A$$ will react to form products which will exert a pressure of 0.4 $$atm$$.
Total pressure increased to $$1.3\: atm$$
Total pressure increased by $$0.3\: atm$$
The difference in mercury level is $$228 \: mm$$.
$$P_{T}=(1 +3 \times 0.1)=1.3\: atm$$
$$\triangle P=0.3\:atm$$ or $$76 \times 0.3\: cm \: of \: Hg$$
or $$760 \times 0.3 =228 \:mm\: of\: Hg$$

Chemistry

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