Question

# A open ended mercury manometer is used to measure the pressure exerted by a trapped gas as shown in the figure. Initially manometer shows no difference in mercury level in both columns as shown in diagram. After sparking $$'A'$$ dissociates according to following reaction $$A(g) \rightarrow B(g) + 3C (g)$$If pressure of Gas $$"A"$$ decreases to $$0.9 \:atm$$. Then:(Assume temperature to be constant and is $$300 K$$)

A
total pressure increased to 1.3atm
B
total pressure increased by 0.3atm
C
total pressure increased by 22.3cm of Hg
D
difference in mercury level is 228mm.

Solution

## The correct options are A total pressure increased to $$1.3\: atm$$ B total pressure increased by $$0.3\: atm$$ D difference in mercury level is $$228\: mm$$.The change in the number of moles $$\Delta n = 4-1=3$$Initial pressure is equal to 76 $$cm$$ of mercury or 1 $$atm$$.$$1-0.9=0.1$$ $$atm$$ of $$A$$ will react to form products which will exert a pressure of 0.4 $$atm$$.Total pressure increased to $$1.3\: atm$$Total pressure increased by $$0.3\: atm$$The difference in mercury level is $$228 \: mm$$.$$P_{T}=(1 +3 \times 0.1)=1.3\: atm$$$$\triangle P=0.3\:atm$$ or $$76 \times 0.3\: cm \: of \: Hg$$or $$760 \times 0.3 =228 \:mm\: of\: Hg$$Chemistry

Suggest Corrections

0

Similar questions
View More

People also searched for
View More