A p-n junction diode is made up of a material which has energy gap of 3.0eV. The maximum wavelength of radiation that can be absorbed by the material is nearly equal to
A
6216A∘
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B
5426A∘
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C
4140A∘
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D
3146A∘
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Solution
The correct option is C4140A∘ Given energy gap is 3eV hν=3eV hcλ=3×1.6×10−19 (hc≃20×10−26) ⇒λ=20×10−264.8×10−19 ⇒λ=4140A∘