Question

# A p-n photodiode is fabricated from a semiconductor with band gap of $$2.8\ eV$$. Can it detect a wavelength of $$6000\ nm$$?

Solution

## Energy band gap $$E=2.8\ eV$$$$E=\dfrac{hc}{\lambda}$$$$\Rightarrow\dfrac{6.6\times10^{-34}\times3\times10^8}{6000\times10^{-9}\times1.6\times10^{-19}}=0.207\ eV$$The energy of a signal of wavelength $$6000\ nm$$ is $$0.207\ eV$$, which is less than $$2.8\ eV$$, the energy band gap of a photodiode. Hence, the photodiode cannot detect the signal.PhysicsNCERTStandard XII

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